2 × 10²⁴ atoms Na₃P
Math
Pre-Algebra
Order of Operations: BPEMDAS
Chemistry
Atomic Structure
Step 1: Define
4 mol Na₃P
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[tex]\displaystyle 4 \ mol \ Na_3P(\frac{6.022 \cdot 10^{23} \ atoms \ Na_3P}{1 \ mol \ Na_3P} )[/tex] = 2.4088 × 10²⁴ atoms Na₃P
Step 4: Check
We are given 1 sig fig. Follow sig fig rules and round.
2.4088 × 10²⁴ atoms Na₃P ≈ 2 × 10²⁴ atoms Na₃P