Question

In the diagram shown,
CDEF is a trapezium,
ABCF is a rectangle,
BD = 9 cm,
AB = 6 cm,
EF = 3 cm,
Perimeter of ABCF = 20 cm.
6 cm
Calculate the area of trapezium CDEF.
You must show all your working.

Answer 1

Answer:

1/2 * (5+3) * 6 = 24 cm^2

Step-by-step explanation:

Perimeter is 20

and it's a rectangle so 2x + 12= 20

x is 4 so one of parallel side of trapezium is 9-4 or 5 then just apply formula for area of trapezium

Answer 2

The area of the trapezium is $60cm^{2}$

What is a trapezium?

'A trapezium is a quadrilateral, which is defined as a shape with four sides and one set of parallel sides.'

According to the given problem,

AB = FC = 6cm

Perimeter of ABCF = 20cm

CB = FA

⇒ 20 = 6 + 6 + CB + CB

⇒ 8 = 2CB

⇒ CB = 4

Base 1 = CF = 6cm

Base 2 = DEDE = DB + BA + AEDB = AEDE = 9 + 6 + 9 = 24

Area = $\frac{1}{2} * ( a + b ) * h$

h = 4a = Base 1 = 6b = DE = 24

Area of trapezium CDEF=$\frac{1}{2}* (6+24)*4$

= $(2*30) cm^{2}$ = $60 cm^{2}$

Hence, we can conclude that the area of the trapezium is 60cm ².

Learn more about area of trapezium here: https://brainly.com/question/13454156

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