Question

Refer to the electron distribution to answer 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹. What would be the period or series number of the atom?

A.6
B.5
C.4
D.3

I need the answer now plss help​

Answer 1

C.5

Given:

Electron distribution: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹.

A number of electrons present in valence shell of penultimate Shell represents the group of elements.

For s block elements: No. of group=number of valence shell electron.

p block elements: no. of group= 2 + 10 + number of valence electrons.

d block elements: no. of group= number(n-1)d electrons + number of electrons in nth shell.

Here, the differential electron is in p orbital hence, it belongs to p block

No. of group= 2+ 10 + 3=15 i.e. 15th group or VA group.

Therefore, the correct option is B.

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