Answer:
The correct option is "Zero". A further explanation is given below.
Explanation:
As we know,
The capacitor is given by:
⇒ [tex]Q=C\times V[/tex]
Rate of change with respect to the time will be:
⇒ [tex]\frac{dQ}{dt}=C\times \frac{dV}{dt}[/tex]
Now,
It is mentioned in the question that the capacitor is completely charged, then
⇒ [tex]\frac{dV}{dt}=0[/tex]
i.e.,
⇒ [tex]\frac{dQ}{dt}=0[/tex]
All other choices available aren't related to that same scenario in question. So the answer above is the perfect one.