Answer:
The final volume of the Nitrogen gas is 54.03 L.
Explanation:
Given;
initial volume of the Nitrogen gas, V₁ = 80 L
initial pressure of the Nitrogen gas, (at STP), P₁ = 101.3 kPa
final pressure of the Nitrogen gas, P₂ = 150 kPa
If the temperature is held constant, apply Boyle's law to determine the final volume of the Nitrogen gas.
V₁P₁ = V₂P₂
[tex]V_2 = \frac{V_1P_1}{P_2} \\\\V_2 = \frac{(80 \ L)(101.3 \ kPa)}{150 \ kPa} \\\\V_2 = 54.03 \ L[/tex]
Therefore, the final volume of the Nitrogen gas is 54.03 L.