Answer:
[tex]Cos \ \theta = \frac{\sqrt{7} }{4}[/tex]
Step-by-step explanation:
Given;
Sin θ = 3/4
To calculated Cos θ;
make a sketch of right-angled triangle with following sides;
opposite side = 3
hypotenuse side = 4
then, the adjacent side will be calculated from Pythagoras theorem;
let the adjacent side = b
b² = 4² - 3²
b² = 16 - 9
b² = 7
b = √7
Therefore, Cos θ is now calculated as;
Cos θ = adjacent / hypotenuse
Cos θ = √7/4
[tex]Cos \ \theta = \frac{\sqrt{7} }{4}[/tex]
Therefore, [tex]Cos \ \theta = \frac{\sqrt{7} }{4}[/tex]