Answer:
Non of the above
I
[tex]f(x) = 4x - 1 \\ f(1) = 4 - 1 \\ f(1) = 3[/tex]
II
[tex]f(x) = 3x - \frac{1}{4} \\ {f}^{ - 1} (x) = \frac{1}{3x} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{6} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{4} [/tex]
III
[tex]2y + 8 = 4y - 2 \\ - 2y = - 10 \\ y = 5[/tex]