Answer: Let, n(U) be=x only (p)=x/5 only(ca)=16 n(pnc)=?n(c)=60%ofx=0.6x
then,
Only (c)=n(c)-n(cnp)
16=0.6x-n(cnp)
n(cnp)=0.6x-16
again,
n(U)=only(p)+only (c)+n(cnp)+n(pUc)of complement
x=x/5+16+0.6x-16+8
5x=x+3x+40
x=40
n(cnp)=0.6x-16=0.6×40-16=8
Step-by-step explanation: