Answer:
83.3m
Explanation:
From the question we are given the following:
initial speed u = 50m/s
acceleration a = -15m/s²
final speed = 0m/s
Required
Stopping distance S
Using the equation of motion:
0² = 50²+2(-15)S
0² = 2500 - 30S
-2500 = -30S
S = 2500/30
S = 83.3m
Hence the stopping distance of the dragster if only the drag chute is used bring it to rest is 83.3m