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Two identical small charged spheres hang in equilibrium with equal masses (0.02kg). The length of the strings is equal (0.18m) and the angle with the vertical is identical (7^o). Find the magnitude of the charge on each sphere. The acceleration of gravity is 9.8 m/s^2 and the value of Coulomb

Respuesta :

Answer:

The value is [tex]q = 3.4 *10^{-6} \ C[/tex]

Explanation:

From the question we are told that

    The mass of each sphere is [tex]m_1 = m_2 = m = 0.020 \ kg[/tex]

     The length of the string is  [tex]l = 0.18 \ m[/tex]

     The angle of with the vertical is [tex]\theta = 7^o[/tex]

      The acceleration due to gravity is [tex]g = 9.8 \ m/s^2[/tex]

Generally the force acting between the forces is mathematically represented as

       [tex]F = T cos \theta = \frac{k* q^2}{ r^2}[/tex]

=>     [tex]T cos \theta = \frac{k* q^2}{ r^2}[/tex]

Generally from Pythagoras theorem the radius of the circular curve created by the force is

         [tex]r = 2 L sin (\theta )[/tex]

=>      [tex]r = 2* 0.180 sin (7)[/tex]

=>      [tex]r = 0.043 \ m[/tex]  

=>     [tex]q = tan \theta * \frac{m * g * r^2 }{k}[/tex]

=>      [tex]q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}[/tex]

=>      [tex]q = 3.4 *10^{-6} \ C[/tex]