Answer:
Explanation:
Step 1
The mass percent of MgCO3 in the original mixture is calculated as shown,
Step 2
Masses of MgCO3 and CaCO3 is 24g; Moles of carbon dioxide produced from Magnesium carbonate and Calcium carbonate are.
Step 3
Adding and equating the moles of Carbon dioxide results in,
Step 4
Percent mass of MgCO3 in the sample is calculated as,