Question

Sulfuric acid, H 2 S O 4 , is an important industrial chemical, typically synthesized in a multi-step process. What is the percent yield if a batch of H 2 SO 4 has a theoretical yield of 3.4 kg, and 2.7 kg are obtained at the end of the process

Answer 1

Answer:

79.4 %

Explanation:

From the question given above, the following data were obtained:

Theoretical yield = 3.4 kg

Actual yield = 2.7 kg

Percentage yield =?

Percentage yield is simply defined as the ratio of the actual yield to that of the theoretical yield multiplied by 100 i.e

Percentage yield = Actual yield/Theoretical yield × 100

With the above formula, we can obtain the percentage yield as follow:

Theoretical yield = 3.4 kg

Actual yield = 2.7 kg

Percentage yield =?

Percentage yield = Actual yield/Theoretical yield × 100

Percentage yield = 2.7/3.4 × 100

Percentage yield = 79.4 %

Thus the percentage yield is 79.4 %

Answer 2

The percent yield is 79.4%

Percentage yield

From the question,

We are to determine the percent yield.

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical yield } \times 100\%$

From the given information,

Actual yield = 2.7 kg

Theoretical yield = 3.4 kg

Putting the parameters into the formula,

$Percent\ yield = \frac{2.7}{3.4} \times 100\%$

Then,

$Percent\ yield = 0.7941176\times 100\%$

$Percent\ yield = 79.4\%$

Hence, the percent yield is 79.4%

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