A 0.2-kg stone attached to a string is swung in a circle with a radius 0.6 m on a horizontal frictionless surface. What is the tension in the string if the stone makes 150 revolutions per minute?

Respuesta :

Answer:

The value is  [tex]T = 29.58 \ N[/tex]

Explanation:

From the question we are told that

      The mass of the stone is  [tex]m = 0.2 \ kg[/tex]

      The radius of the circle is [tex]r = 0.6 \ m[/tex]

      The angular speed is  [tex]w = 150 \ rpm = \frac{ 2 * \pi * 150 }{ 60 } = 15.7 \ rad/s[/tex]

Generally the tension in the string is mathematically represented as

           [tex]T = m * r * w ^2[/tex]

=>        [tex]T = 0.2 * 0.6 * 15.7 ^2[/tex]

=>        [tex]T = 29.58 \ N[/tex]

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