Question

Differentiate the following using the first principle :
(i) y = x — (1/x)
(ii) y= x¹/³
Pls help, needed urgently.

Answer 1

Answer:

Derivative of i is y' =1 - $\frac{1}{x^{2} }$

As for the second function, I'm confused by what you typed please retype it correctly so I can solve

Step-by-step explanation:

Work for the first derivative:

i. y = x - (1/x) = x - $x^{-1}$

y' = $x^{1-1} = x^{0} = 1\\\\\\x^{-1-1} =x^{-2} = \frac{1}{x^{2} }$

y' = $1 -\frac{1}{x^{2} }$