Question

I need help!!!!!!What is the average rate of change of g over the interval – 4 < t < 1?
Give an exact number.

Answer 1

Answer:

-0.4.

Step-by-step explanation:

Average rate of change = difference in g(x) / difference in x

= (0 - 2) / (1 - (-4))

= -2/5 or -0.4.

Answer 2

The average rate of change of g over the interval -4 < t < 1 is -0.4

What is rate of change?

'A rate of change is a rate that describes how one quantity changes in relation to another quantity.'

According to the given problem,

Interval = -4 < t < 1

We know,

rate of change = $\frac{y_{2}- y_{1} }{x_{2}-x_{1} }$

y₂ = 0

y₁ = 2

x₂ = 1

x₁  = -4

Rate of change = $\frac{0-2}{1-(-4)}$

                          = $\frac{-2}{5}$

                          = - 0.4

Hence, we can conclude, the average rate of change over the given interval is -0.4.

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