The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is closest to:

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Answer:

Ok:

Explanation:

So, you can use the Henderson-Hasselbalch equation for this:

pH = pKa + log([tex]A^-/HA[/tex]) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

1 = log([tex]A^-/HA\\[/tex]) and so 10 = [tex]A^-/HA[/tex] or 10HA = A-.  For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.

Nucleoside is "a structural subunit of nucleic acids, the heredity-controlling components of all living cells, consisting of a molecule of sugar linked to a nitrogen-containing organic compound".

What are nucleic acids?

Nucleic acids are "naturally occurring chemical compounds that serve as the primary information-carrying molecules in cells".

What is nitrogen?

Nitrogen is "an essential element for all forms of life and is the structural component of amino acids from which animal and human tissues, enzymes, and many hormones are made".

What is organic compound?

Organic compound is "any of a large class of chemical compounds in which one or more atoms of carbon are covalently linked to atoms of other elements, most commonly hydrogen, oxygen, or nitrogen".

Using Henderson-Hasselbalch equation

pH = pKa + log(A⁻/HA)

where pH is the concentration of [H⁺]

           pKa is the acid dissociation constant and [A⁻] and [HA] are the concentrations of conjugate base and an acid.

1 = log (A⁻/HA)

Thus, 10 = A⁻/HA

10HA = A⁻ Each protonated form of adenosine (HA) contains 10 A⁻

Hence, the percentage of the protonated form at pH 4.8 will be 1(1+10) or 1/11 which is closer to 9 percent.

To learn more about nucleoside here

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