(a ² + b ²) / (ab) = a/b + b/a = (√3 - √2) + 1/(√3 - √2)
Rationalize the denominator of the second term:
1/(√3 - √2) • (√3 + √2)/(√3+√2) = (√3 + √2)/((√3)² - (√2)²) = √3 + √2
So we have
(a ² + b ²) / (ab) = (√3 - √2) + (√3 + √2) = 2√3
