Respuesta :
Step-by-step explanation:
Note that t = d/r where t is time, d is distance, and r is rate/speed.
We can come up with two equations with the information given and the equation:
t_1 hr = (10 km)/(x km/hr)
t_2 hr = (12 km)/(x - 1 km/hr)
where t_1 is the time taken to run the 10km the first day and t_2 is the time taken to run the 12km the second day.
We know that 30 minutes is 1/2 of an hour and that t_1 is 30 minutes less than t_2 (as stated in the question). Therefore, we can write:
t_1 = t_2 - 1/2
Substituting the values we derived:
(10 km)/(x km/hr) = (12 km)/(x - 1 km/hr) -1/2
Then we can evaluate by multiplying by 2x(x-1) on both sides:
20(x-1) = 24x - (x)(x-1)
20x - 20 = 24x - x^2 + x
x^2 -5x -20 = 0
And we are done.
I hope this helps! :)
An equation is formed when two equal expressions. The equation for the time can be written as (12/x-1)-(10/x)=0.5. The value of x is 7.623.
What is an equation?
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
A.) Given Alfonso runs 10 km at an average speed of x km/h. Therefore, the time taken by Alfonso to rum 10km is 10/x hour.
Also, The next day he runs 12 km at an average speed of (x - 1) km/h. Therefore, the time taken by Alsonso to run 12km is 12/(x-1) hour.
Now, the time taken for the 10km run in 30minutes(0.5 hours) is less than the time taken for the 12 km run. Therefore, we can write,
[tex]\dfrac{12}{(x-1)}-\dfrac{10}{x} =0.5[/tex]
The equation for the time can be written as (12/x-1)-(10/x)=0.5.
B.) The value of x can be written as,
[tex]\dfrac{12}{(x-1)}-\dfrac{10}{x} =0.5\\\\12x-10(x-1)=0.5 \times x \times (x-1)\\\\12x - 10x +10 = 0.5x^2-0.5x\\\\2x+10 = 0.5x^2-0.5x\\\\0=0.5x^2 - 2.5x -10\\\\x = -2.623, 7.623[/tex]
Since the time can not be negative. Hence, the value of x is 7.623.
Learn more about Equation:
https://brainly.com/question/2263981
#SPJ2