Answer:
a. [tex]Probability = 0.2496[/tex]
b. No, it won't change
Step-by-step explanation:
Represent [tex]the\ head[/tex] with H and [tex]Tail\ with[/tex] T
Such that:
[tex]P(H) = 48\%[/tex]
Solving (a): First head in second trial
First, we determine P(T) i.e. the probability of obtaining a tail
[tex]P(H)+P(T) = 100\%[/tex]
[tex]P(T) = 100\% -P(H)[/tex]
Substitute 48% for P(H)
[tex]P(T) = 100\% -48\%[/tex]
[tex]P(T) = 52\%[/tex]
If the first head is obtained in the second trial, the probability is:
[tex]Probability = P(T\ and\ H)[/tex]
[tex]Probability = P(T)\ and\ P(H)[/tex]
[tex]Probability = P(T)\ *\ P(H)[/tex]
[tex]Probability = 48\%* 52\%[/tex]
[tex]Probability = 0.2496[/tex]
Solving (b): Will it change if tossed three or four times?
Irrespective of the number of times the coin is tossed, the probability of obtaining a head in the second toss will always be the same because the coin has to be tossed twice before the third and the fourth time.