gfredmoore9254 gfredmoore9254
  • 31-12-2020
  • Mathematics
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the question is below

the question is below class=

Respuesta :

jimrgrant1 jimrgrant1
  • 31-12-2020

Answer:

sin I = [tex]\frac{80}{89}[/tex]

Step-by-step explanation:

sin I = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KJ}{JI}[/tex] = [tex]\frac{80}{89}[/tex]

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