Simon entered a number into his calculator. To this number, he added the square of the original number and the cube of the original number. Simon got the answer 543.192 Use a trial and improvement method to find the number that Simon first entered into his calculator.

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Answer:

7.8. First plug in a number, then just keep trying till you get 7.8

The number is 7.79999 that Simon first entered into his calculator if this number, he added the square of the original number and the cube of the original number.

What is the trial and error method?

A significant way of problem-solving is trial and error. It is defined by repeated, varied attempts that are made until the practicer succeeds or stops attempting.

Let's suppose the number is x

Then according to the problem a polynomial equation can be framed:

[tex]\rm x+x^2+x^3= 543.192[/tex]

Let's plug x = 6, we get:

[tex]\rm 6+6^2+6^3= 543.192[/tex]

= 258

x = 6 is not the solution

Let's plug x = 7, we get:

[tex]\rm 7+7^2+7^3= 543.192[/tex]

=399

x = 7 is not the solution

If plus x = 8, we will get 584 which is greater than 543.192

Let's plug x = 7.5, we will get 485.625 which is less than 543.192

Let's plug x =  7.79999 we will get 543.190 which is very close to 543.192

Thus, the number is 7.79999 that Simon first entered into his calculator if this number, he added the square of the original number and the cube of the original number.

Learn more about the trial and error method here:

https://brainly.com/question/4123314

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