Respuesta :
Answer:
(c) 1.5 x 10^4 C
Explanation:
we have,
P=1kW=1000w
V=240V
therefore,
P=V *I
1000=240*I
I=1000/240
I=25/6A
now,we know that
I =Q/T
Q=IT
Q=25/6*60*60. [since time =1hour i.e 60*60sec]
Q=15000C
Q=1.5 x 10^4C
The required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.
Given data:
The voltage supply of the electric fire is, V' = 240 V.
The rate of energy transfer is, E' = 1.0 kW = 1000 W.
The time interval is, t = 1 h = 60 × 60 = 3600 s.
In this problem, the energy passes through the fire is nothing but the electric charges. For that we need to calculate the value of charge. So, first calculate the current flow as,
E' = V × I
Solving as,
1000 = 240 × I
I = 1000/240
I = 4.167 A
Now, the energy passes through the fire is obtained as,
Q = I × t
Q = 4.167 × 3600
[tex]Q = 1.5 \times 10^{4} \;\rm C[/tex]
Thus, we can conclude that the required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.
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