Mass of water vapor = 193 g
Given
435 kJ of heat are released
Required
mass of water vapor
Solution
The heat to change the phase can be formulated :
Q = mLf (melting/freezing)
Q = mLv (vaporization/condensation)
Lv for water = 2256 kJ/kg or 2256 J/g or 40.7 kJ/mol
So the mass of water vapor :
[tex]\tt m=\dfrac{Q}{Lv}\\\\m=\dfrac{435000~J}{2256~J/g}\\\\m=192.8\approx 193~g[/tex]