Answer:
The sum of the two digits integers which divide 109 with a remainder of 4 is 71
Step-by-step explanation:
The given parameters are;
109/x = Q + 4/x
Therefore, we have;
109 = Q·x + 4
∴ Q·x = 109 - 4 = 105
x = 105/Q
Therefore, x is a factor of 105
The possible two digits integers which x represents includes the two digit factors of 105 which are;
15, 21, and 35
Which gives;
15 × 7 = 105
21 × 5 = 105
35 × 3 = 105
The sum of the two digits integers which divide 109 with a remainder of 4 is 15 + 21 + 35 = 71.
