Answer:
Her raise per hour is $3.
Step-by-step explanation:
Quadratic Equation
The standard representation of a quadratic equation is:
[tex]ax^2+bx+c=0[/tex]
where a,b, and c are constants.
It can be solved by using the quadratic formula:
[tex]\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Jill asks for an increase in the hourly wage she receives. Since she works in a Maths Center, the increase comes as a maths equation.
She must solve the equation:
[tex]x^2-6x+9=0[/tex]
The solution to the equation is the increase in her hourly wage.
Comparing with the general form, we have a=1, b=-6, c=9. Thus, the solutions are:
[tex]\displaystyle x=\frac{-(-6)\pm \sqrt{(-6)^2-4(1)(9)}}{2(1)}[/tex]
[tex]\displaystyle x=\frac{6\pm \sqrt{36-36}}{2}[/tex]
[tex]\displaystyle x=\frac{6\pm \sqrt{0}}{2}[/tex]
Since the square root is 0, there is only one solution:
[tex]\displaystyle x=\frac{6}{2}=3[/tex]
x = 3
Thus, her raise per hour is $3.