Answer:
Following are the solution to the given points:
Explanation:
In this question, some of the values are missing, that's why its solution can be defined as follows:
In point a:
Density of air [tex]\rho_{air} =1.29 \frac{kg}{m^3}\\\\[/tex]
Density of helium [tex]\rho_{helium} =0.178 \frac{kg}{m^3} \\\\[/tex]
The volume of the helium balloon [tex]V= 2L[/tex]
[tex]\to V= 2 \times 10^{-3}[/tex]
Formula:
[tex]F_B = e_a V g\\\\[/tex]
[tex]= 1.29 \times 2 \times 10^{-3} \times 9.81\\\\ = 0.0253098 \ N[/tex]
where g is the acceleration due to gravity
In point b:
[tex]m_g= 1.5 \ g[/tex]
Formula:
[tex]F_{net}=F_B - (m_r + \rho_h \ v )g[/tex]
[tex]= 0.0253098 - (1.5 \times 10^{-3} + 0.178 \times 2 \times 10^{-3} \times 9.81)\\\\= 7.10244 \times 10^{-3} \ N[/tex]