Respuesta :

Answer:

C. No, because it's determinant is zero

Step-by-step explanation:

[tex]A= \begin{bmatrix} 16 & - 4\\\\ 8 & - 2\end{bmatrix} [/tex]

[tex] det(A) =\begin{vmatrix} 16 & - 4\\\\ 8 & - 2\end{vmatrix} [/tex]

[tex] det(A) = 16\times (-2)-(-4)\times 8[/tex]

[tex] det(A) = -32+32[/tex]

[tex] det(A) = 0[/tex]

This matrix have no inverse, because it's determinant is zero.

It is given a 2*2 matrix of order 2.

To find this matrix have an inverse or not.

What is determinant?

A quantity obtained by the addition of products of the elements of a square matrix according to a given rule.

The given matrix is

A= [tex]\left[\begin{array}{ccc}16&-4\\8&-2\\\end{array}\right][/tex]

det A=16*(-2)-(-4)*8=0

det A=0

So, this matrix have no inverse, because it's determinant is zero.

Learn more about determinant here:

https://brainly.com/question/20367047

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