How many moles of O2 are needed to react
with 24 moles of C2H6?
2C2H6 + 702 — 4CO2 + 6H20

Explanation:
Mole ratio of Ethane to Oxygen = 2 : 7
Moles of O2 needed = 24 moles * (7/2) = 84 moles.
Moles are the ratio of the mass and the molar mass of the substance. 84 moles of oxygen are needed to react with Ethane.
Moles are the unit of the measurement of small entities like molecules, atoms, or particles.
The reaction is shown as:
[tex]\rm 2C_{2}H_{6} +7O_{2} \rightarrow 4CO_{2} + 6H_{2}O[/tex]
From the reaction, it can be said that the mole ratio of ethane [tex](\rm C_{2}H_{6})[/tex] and oxygen [tex](\rm O_{2})[/tex] is 2:7.
Then moles of oxygen will be,
[tex]24 \times \dfrac{7}{2} = 84[/tex]
Therefore, 84 moles of oxygen are needed to react with 24 moles of ethane.
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