Respuesta :

Answer:

C4H8O4

Explanation:

Let (CH20)x

C=1*12.01=12.01     (12.01, 1.01, 16.00 Avg mass of elements)

H=2*1.01=2.01

O=1*16.00=16.00

12.01 + 2.01 + 16.00 = 30.03

120.12/30,03=4

==> (CH2O)4 = C4H8O4

Lanuel

The molecular formula of the molecule that has an empirical formula of [tex]CH_2O[/tex] is equal to [tex]C_4H_8O_4[/tex].

Given the following data:

  • Empirical formula = [tex]CH_2O[/tex]
  • Molar mass = 120.12 g/mol.

Scientific data:

  • Molar mass of oxygen = 16 g/mol.
  • Molar mass of hydrogen = 1 g/mol.
  • Molar mass of carbon = 12 g/mol.

To determine the molecular formula of the molecule that has an empirical formula of [tex]CH_2O[/tex]:

First of all, we would find the molar mass of [tex]CH_2O[/tex]:

[tex]CH_2O =12 +(1\times2)+16\\\\CH_2O =30\;g/mol[/tex]

For molecular formula:

[tex](CH_2O)n = 120.12\\\\30n = 120.12\\\\n=\frac{120.12}{30}[/tex]

n = 4.0

[tex](CH_2O)_4 = C_4H_8O_4[/tex]

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