Respuesta :
Answer:
C4H8O4
Explanation:
Let (CH20)x
C=1*12.01=12.01 (12.01, 1.01, 16.00 Avg mass of elements)
H=2*1.01=2.01
O=1*16.00=16.00
12.01 + 2.01 + 16.00 = 30.03
120.12/30,03=4
==> (CH2O)4 = C4H8O4
The molecular formula of the molecule that has an empirical formula of [tex]CH_2O[/tex] is equal to [tex]C_4H_8O_4[/tex].
Given the following data:
- Empirical formula = [tex]CH_2O[/tex]
- Molar mass = 120.12 g/mol.
Scientific data:
- Molar mass of oxygen = 16 g/mol.
- Molar mass of hydrogen = 1 g/mol.
- Molar mass of carbon = 12 g/mol.
To determine the molecular formula of the molecule that has an empirical formula of [tex]CH_2O[/tex]:
First of all, we would find the molar mass of [tex]CH_2O[/tex]:
[tex]CH_2O =12 +(1\times2)+16\\\\CH_2O =30\;g/mol[/tex]
For molecular formula:
[tex](CH_2O)n = 120.12\\\\30n = 120.12\\\\n=\frac{120.12}{30}[/tex]
n = 4.0
[tex](CH_2O)_4 = C_4H_8O_4[/tex]
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