Question

500 mL of He at 98 kPa expands to 750 mL.

Answer 1

500 mL of He at 98 kPa expands to 750 mL. Find P2.

P₂ = 65.3 kPa

Further explanation

Given

V₁=500 ml

P₁=98 kPa

V₂=750 ml

Required

P₂

Solution

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

Input the value :

$\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_1=\dfrac{98.500}{750}\\\\P_2=65.3~kPa$