Question

Which is the graph of f(x) = RootIndex 3 StartRoot x EndRoot – 4?

Answer 1

Answer:

Graph shown below

Step-by-step explanation:

Cubic Root Graph

The graph of the function

$f(x)=\sqrt[3]{x}-4$

Is shown in the attached image. Some points are calculated below:

We'll take x={-8,-1,0,1,8}:

$f(-8)=\sqrt[3]{-8}-4=-2-4=-6$

Point (-8,-6)

$f(-1)=\sqrt[3]{-1}-1=-1-4=-5$

Point (-1,-5)

$f(0)=\sqrt[3]{0}-4=0-4=-4$

Point (0,-4)

$f(1)=\sqrt[3]{1}-1=1-4=-3$

Point (1,-3)

$f(8)=\sqrt[3]{8}-1=2-4=-2$

Point (8,-2)

Answer 2

The graph of $\rm f(x) = \sqrt[3]{x} - 4$ is attached below and this can be sketched by substituting the values of x in the function f(x) and then plotting the points on the graph.

Given :

$\rm f(x) = \sqrt[3]{x} - 4$

The following steps can be used in order to determine the graph of the given function f(x):

Step 1 - Determine the value of f(x) at the values of x = {-8,-4,0,4,8}.

Step 2 - At (x = -8) the value of f(x) is given by:

$\rm f(x) = \sqrt[3]{-8} - 4$

$\rm f(x) = -2 - 4 = -6$

Step 3 - At (x = -4) the value of f(x) is given by:

$\rm f(x) = \sqrt[3]{-4} - 4$

f(x) = -5.6

Step 4 - At (x = 0) the value of f(x) is given by:

$\rm f(x) = \sqrt[3]{0} - 4$

f(x) = -4

Step 5 - At (x = 4) the value of f(x) is given by:

$\rm f(x) = \sqrt[3]{4} - 4$

f(x) = -2.4

Step 6 - At (x = 8) the value of f(x) is given by:

$\rm f(x) = \sqrt[3]{8} - 4$

f(x) = -2

Step 7 - Now, plot the points obtained in the above steps on the graph in order to draw the graph of the given function $\rm f(x) = \sqrt[3]{x} - 4$

The of the function $\rm f(x) = \sqrt[3]{x} - 4$ is attached below.

For more information, refer to the link given below:

https://brainly.com/question/4700926