Answer:
v₀ = 3.77 [m/s]
Explanation:
This problem can be solved in a simple way by means of the following equation of kinematics.
[tex]y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}[/tex]
where:
y - yo = 0.441 [m]
Vo = initial velocity [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 0.625 [s]
[tex]0.441 = v_{o}*(0.625)-\frac{1}{2} *9.81*(0.625)^{2} \\2.357 = v_{o}*0.625\\v_{o}=3.77[m/s][/tex]
Note: The sign of the acceleration is negative since the movement of the basketball player is against of the gravity acceleration.
