Question

A heat lamp produces 32.8 watts of power at a wavelength of 6.5 mm. How many photons are emitted per second

Answer 1

Answer: 1.1x10^21 photons / sec

Explanation:energy per photon

.. E / photon = hc / L = (6.626x10^-34 J x sec) x (3.00x10^8 m/sec) / (6.5x10^-6m)

.. E / photon = 3.06x10^-20 J / photon

then

.. (32.7 watts) x (1 J/sec / 1watt) x (1 photon / 3.06x10^-20J) = 1.1x10^21 photons / sec

Answer 2

The number of photons are emitted per second will be "1.07".

According to the question,

Power,

• P = 32.8 watts

           = 32.8 J/s

Wave length,

• λ = 6.5 μm

          = $6.5\times 10^{-6}$

As we know,

→ $E = \frac{hc}{\lambda}$

By substituting the values, we get

      $= \frac{32.8}{\frac{(4.42\times 10^{-34})(3\times 10^{-4})}{4.5\times 10^{-6}} }$

      $= \frac{32.8}{3.055e}$

      $= 1.07$

Thus the above answer is correct.

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