Answer:
The determinant of C is zero and does not have inverse.
Step-by-step explanation:
Let [tex]C = \left[\begin{array}{ccc}2&4&6\\3&6&9\\4&8&12\end{array}\right][/tex], since it is a matrix with 3 rows and 3 columns, we can determine its determinant by the Sarrus' rule:
[tex]\det(C) = \left|\begin{array}{ccc}2&4&6\\3&6&9\\4&8&12\end{array}\right|[/tex]
[tex]\det(C) = (2)\cdot (6)\cdot (12)+(3)\cdot (8)\cdot (6)+(4)\cdot (4)\cdot (9)-(4)\cdot (6)\cdot (6)-(3)\cdot (4)\cdot (12)-(2)\cdot (8)\cdot (9)[/tex]
[tex]\det (C) = 0[/tex]
Since the determinant of C is equal to zero, then we conclude that C does not have an inverse according to the following definition of inverse matrix. That is:
[tex]C^{-1} = \frac{1}{\det(C)}\cdot adj(C)[/tex] (1)
Where [tex]adj(C)[/tex] is the adjugate matrix of C, defined as the transpose of the cofactor matrix of C.
The result of this expression is undefined due to the determinant.