Question

10
The reaction in which ammonia is formed is N2(g) + 3H2(g) + 2NH3(). At equilibrium, a
1-L flask contains 0.15 mol H. 0.25 mol N, and 0.10 mol NH. Calculate K., for the reaction.
11.85
23.8
25.0
16

Answer 1

The equilibrium constant (K) : 11.85

Further explanation

Given

Reaction

N₂(g) + 3H₂(g) ⇒ 2NH₃(g)

Required

K(equilibrium constant)

Solution

The equilibrium constant (K) is the value of the concentration product in the equilibrium

The equilibrium constant based on concentration (K) in a reaction  

pA + qB -----> mC + nD  

$\tt K=\dfrac{[C]^m[D]^n}{[A]^p[B]^q}$

For the reaction above :

$\tt K=\dfrac{[NH_3]^2}{[N_2][H_2]^3}\\\\K=\dfrac{0.1^2}{0.25\times 0.15^3}\\\\K=11.85$