Answer:
[tex](\frac{32}{243})^{-\frac{4}{5}}=39.0625[/tex]
Step-by-step explanation:
Given
[tex](\frac{32}{243})^{-\frac{4}{5}}[/tex]
Required
Solve
[tex](\frac{32}{243})^{-\frac{4}{5}}[/tex]
Express 32 as 2^5 and 243 as 3^5
[tex](\frac{2^5}{3^5})^{-\frac{4}{5}}[/tex]
The exponent can be expressed as 1\5 * -4
So we have:
[tex](\frac{2^5}{3^5})^{\frac{1}{5} * -4}[/tex]
Apply law of indices:
[tex](\frac{2^{5*1/5}}{5^{5*1/5}})^{-4}[/tex]
[tex](\frac{2}{5})^{-4}[/tex]
In indices:
[tex](\frac{a}{b})^{-c} = (\frac{b}{a})^{c}[/tex]
So, the expression becomes
[tex](\frac{5}{2})^{4}[/tex]
[tex](\frac{5^{4}}{2^{4}})[/tex]
[tex]\frac{625}{16}[/tex]
[tex]39.0625[/tex]
Hence:
[tex](\frac{32}{243})^{-\frac{4}{5}}=39.0625[/tex]
