Question

At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.
Calculate the distance travelled by car.
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Answer 1

Answer:

62.5m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 5s

Acceleration  = 5m/s²

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use the motion equation given below:

S = ut + $\frac{1}{2}$ at²

S is the distance traveled

u is the initial velocity

a is the acceleration

t is the time taken

Now, insert the parameters and solve;

 S =( 0 x 5) +( $\frac{1}{2}$ x 5 x 5²) = 62.5m