Find the area of the triangle.

Answer:
(D). 5 km²
Step-by-step explanation:
QR² = 11² + 14² - 2(11)(14)cos77°
QR ≈ 15.739 km
P = 14 + 11 + 15.739 = 40.739 km
s = [tex]\frac{P}{2}[/tex] ≈ 20.37 km
[tex]A_{PQR}[/tex] = [tex]\sqrt{20.37(20.37-11)(20.37-14)(20.37-15.739)}[/tex] ≈ 75 km²