Question

3i(4 - I) + i(6 + 2i)

Answer 1

Answer:

-1 + 18i

Step-by-step explanation:

⟺ Distribute 3i and i in the expressions.

$12i-i^2+6i+2i^2\\i^2+18i$

⟺ The define of complex number is

$i^2=-1$

Thus, convert i² to -1

$-1+18i$