Answer:
The value is [tex]v = 0.2857 \ m/s[/tex]
Explanation:
From the question we are told that
The first position is [tex]x_1 = 2 \ m[/tex]
The second position [tex]x_ 2 = 6 \ m[/tex]
The time taken is [tex]t = 14 \ s[/tex]
Generally the average velocity is mathematically represented as
[tex]v = \frac{ x_2 - x_1 }{ t }[/tex]
=> [tex]v = \frac{ 6 -2 }{ 14 }[/tex]
=> [tex]v = 0.2857 \ m/s[/tex]
