Question

Complete the function digits(n) that returns how many digits the number has. For example: 25 has 2 digits and 144 has 3 digits

Answer 1

Answer:

Step-by-step explanation:

We can get this done by using the code

def digits(n):

count = 0

if n == 0:

return 1

while (n > 0):

count += 1

n= n//10

return count

Also, another way of putting it is by saying

def digits(n):

return len(str(n))

------------------------------------------

print(digits(25)) # Should print 2

print(digits(144)) # Should print 3

print(digits(1000)) # Should print 4

print(digits(0)) # Should print 1

Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.

Thanks

Answer 2

Following are the digits function that calculte the digits:

Program Explanation:

• In this question, we define two in which one use predefine methods and one is used for calculate value by logics, which can be defined as follows:
• Defining a method "digits" that takes "n" variable inside the parameter.
• Inside the method "x"variable that converts parameter value into string and counts its length value and use return keyword that return the length of x.
• Outside the method, a variable n is define that inputs value, and call the method and print its return value.

Program:

def digits(n):#defining a method digits that takes n variable in the parameter

   x=len(str(n))#defining a variable x that converts parameter value into string and counts its length value

   return x#using return keyword that return the length of x

n=int(input("Ennter number: "))#defining a variable n that inputs value

print(n, "has", digits(n) ,"digits") #using print method that calls the digits method and print its value

OR

def digits(n):#defining a method digits that takes n variable in the parameter

   x = 0#defining an integer variable x

   if n == 0:#defining an if block that checks n value equal to 0

       return 1#return value 1

   while (n > 0):#defining a while loop that check n value grater than 0

       x += 1#incrementing the value of x

       n =n//10#calculating the digits

   return x#return digits value

n=int(input("Ennter number: "))#defining a variable n that inputs value

print(n, "has", digits(n) ,"digits") #using print method that calls the digits method and print its value

Output:

Please find the attached file.

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