Question

A 2.20-kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring.(a) Determine the force constant of the spring, if the box compresses the spring 6.70 cm before coming to rest.

Answer 1

Answer:

1587.9 N/m

Explanation:

Using the relation :

0.5mv² = 0.5kx²

m = 2.20 kg ;

v = 1.8 m/s ;

x = extension = 6.7cm = 6.7/ 100 = 0.067 m

K = Force constant control f the spring

0.5 * 2.20 * 1.8^2 = 0.5 * k * 0.067^2

3.564 = 0.0022445k

K = 3.564 / 0.0022445

K = 1587.8814

K = 1587.9 N/m