Question

Find the median of the following number of points deducted from a random sample of algebra
midterms.
12, 14,0, 2, 17,7,3, 14, 15

Answer 1

Answer:

$\boxed {\boxed {\sf Median: 12}}$

Step-by-step explanation:

The median is the middle number of a data set.

1. Arrange the data in ascending order (least to greatest)

• Data Set: 12, 14, 0, 2, 17, 7, 3, 14, 15
• Least to Greatest: 0, 2, 3, 7, 12, 14, 14, 15, 17

2. Take one number off each end of the data until the middle is reached.

• 0, 2, 3, 7, 12, 14, 14, 15, 17
• 2, 3, 7, 12, 14, 14, 15
• 3, 7, 12, 14, 14
• 7, 12, 14
• 12

The median of this data set is 12

Answer 2

Answer :

12 is the median of given data.

Solution :

Given data : 12, 14, 0, 2, 17, 7, 3, 14, 15

The middle term of data in ascending order is it's median.

First of all, arrange the data in ascending order.

Ascending order : 0, 2, 3, 7, 12, 14, 14, 15, 17

Now, count total number of terms in given data :

Here, total number of terms, n = 9.

As, we have total number of terms as a odd number.

So, by applying formula :

$\large \underline{\boxed{\sf{Median = \dfrac{n+1}{2} th \: term}}}$

$\sf : \implies Median = \dfrac{9+1}{2} th \: term$

$\sf : \implies Median = \dfrac{\cancel{10}^{5}}{\cancel{2}} th \: term$

$\sf : \implies Median = 5 th \: term$

Now, let's count 5th term :

0, 2, 3, 7, 12, 14, 14, 15, 17

Here, 5th term is 12.

So, The median of this data is 12.