Answer:
16 ft
Step-by-step explanation:
Let the width of the rectangle be x ft
Therefore, length = (x + 2) ft
Area of the rectangle = 15 square ft
[tex]x(x + 2) = 15 \\ \\ {x}^{2} + 2x = 15 \\ \\ {x}^{2} + 2x - 15 = 0 \\ \\ {x}^{2} + 5x - 3x - 15 = 0 \\ \\ x(x + 5) - 3(x + 5) = 0 \\ \\ (x + 5)(x - 3) = 0 \\ \\ x + 5 = 0 \: or \: \: x - 3 = 0 \\ \\ x = - 5 \: \: or \: \: x = 3 \\ \\ \because \: x \: can \: not \: be \: - ve \\ \\ \therefore \: x = 3 \\ \\ \implies \: x + 2 = 3 + 2 = 5 \\ \\ perimeter \: of \: rectngle \\ = 2(5 + 3) \\ = 2 \times 5 \\ = 16 \: ft[/tex]
