Answer:
The function which represents this sequence will be:
[tex]a_n=-15n+110[/tex]
Hence, option (A) is true.
Step-by-step explanation:
Given the sequence
[tex]95, 80, 65, 50, ...[/tex]
An arithmetic sequence has a constant difference 'd' and is defined by
[tex]a_n=a_1+\left(n-1\right)d[/tex]
computing the differences of all the adjacent terms
[tex]80-95=-15,\:\quad \:65-80=-15,\:\quad \:50-65=-15[/tex]
As the difference is the same, so
[tex]d = -15[/tex]
as
[tex]a_1=95[/tex]
Thus, substituting [tex]d = -15[/tex], [tex]a_1=95[/tex] in the nth term of an arithmetic sequence
[tex]a_n=a_1+\left(n-1\right)d[/tex]
[tex]a_n=-15\left(n-1\right)+95[/tex]
[tex]a_n=-15n+110[/tex]
Therefore, the function which represents this sequence will be:
[tex]a_n=-15n+110[/tex]
Hence, option (A) is true.