Question

If a normal distribution has a mean of 62 and a standard deviation of 12, what
is the z-score for a value of 74?

Answer 1

Step-by-step explanation:

N~(62, 12^2)

Use Z-score formula (can find in internet)

$z = \frac{74 - 62}{12} \\ z = \frac{12}{12} \\ z = 1$