Question

HELP ASAP
1. n animal rescue center has an adoption event. People adopt 84 animals at the event, which is 70% of the animals at the center. What was the total number of animals at the adoption center before the adoption event?


a 60

b 120

c 92

d 160

2. Mr. Baker spends $36 at Walmart buying snacks for the big game. This is 75% of the total amount of cash that he has in his pocket. How much money did Mr. Baker have in his pocket before he purchased snacks at Walmart?


a $12

b $18

c $60

d $48

3. 40% of what number is 24?

Answer 1

9514 1404 393

Answer:

1. b  120
2. d  $48
3. 60

Step-by-step explanation:

Each of these problems is worked the same way. They are all of the form ...

  given value = percentage × unknown

The solution is found by dividing by the coefficient of "unknown", that is, you divide the given value by the percentage.

  (given value)/percentage = unknown

__

1. 84/0.70 = 120 . . . matches b

__

2. $36/0.75 = $48 . . . matches d

__

3. 24/0.40 = 60

Answer 2

Answer:

1. b 120, 2. d $48 3. 60

Step-by-step explanation:

1.

Let $x =$ total number of animals at the adoption centre

$0.7x = 84$

$x = 84 \div 0.7\\= 120$

$\therefore$ b is the correct answer

2.

Let $c =$ total amount of cash Mr. Baker has

$0.75c = 36$

$c = 36\div0.75$

$= 48$

$\therefore$ d is the correct answer

3.

Let $x =$ the number you are trying to find

$0.4x = 24$

$x = 24\div0.4$

$=60$

$\therefore 40$ percent of $60$ is $24$

Hope this helps :)