Question

Box со
1. A man had three GH¢50,00, seven GH¢20.00 and five GH¢10.00 notes in his
pocket, if he bought a bicycle for GH¢80.00 each, how many GH¢20.00 and
GH¢10.00 notes did he have left?
​

Answer 1

Answer:

The man has 6 GHc20.00 notes and 4 GHc10.00 left

Step-by-step explanation:

Given

Amount = 3 GH¢50.00, 7  GH¢20.00 and 5 GH¢10.00

Spendings = GH¢80,00

Required

Determine how many GH¢20.00 and  GH¢10.00 notes left

The amount he has can be represented as:

$Amount = 3 * GHc50.00 + 7 * GHc20.00 + 5 * GHc10.00$

$Spendings = GHc80.00$

This can be represented as:

$Spendings = GHc50.00+GHc20.00+GHc10.00$

Represent:

GHc50.00 with x, GHc20.00 with y and GHc10.00 with z

So, we have:

$Amount = 3 * GHc50.00 + 7 * GHc20.00 + 5 * GHc10.00$

$Amount = 3 *x + 7*y + 5*z$

$Amount = 3x + 7y + 5z$

$Spendings = GHc50.00+GHc20.00+GHc10.00$

$Spendings =x+y+z$

Subtract the spendings from the total to get amount left

$Amount\ Left= 3x + 7y +5z - (x+y+z)$

$Amount\ Left= 3x + 7y +5z - x-y-z$

Collect Like Terms

$Amount\ Left= 3x-x + 7y-y +5z-z$

$Amount\ Left= 2x + 6y +4z$

Recall that, we have represented:

GHc50.00 with x, GHc20.00 with y and GHc10.00 with z

This means that, the man has 6 GHc20.00 notes and 4 GHc10.00 left