Respuesta :
Answer:
The answer is "[tex]5x+10y+5z[/tex]"
Step-by-step explanation:
Given value:
[tex]\to \frac{1}{2}(10x + 20y +10z)[/tex]
Using the distributive property.
If there are three integers a,b and c then:
[tex]a \cdot(b+c) =a \cdot b + a \cdot c[/tex]
[tex]\to \frac{1}{2}(10x) +\frac{1}{2}(20y+10z)\\\\\to (5x) +\frac{1}{2}(20y+10z)[/tex]
Again apply the distributive property
[tex]\to (5x) +(10y+5z)\\\\\to (5x+10y+5z)[/tex]
Or
[tex]\to \frac{1}{2}(10x + 20y +10z)[/tex]
take common 2 from the equation:
[tex]\to \frac{1}{2}\times 2 (5x + 10y +5z)\\\\\to (5x + 10y +5z)\\[/tex]