Apply the distributive property to create an equivalent expression. \dfrac12(10x + 20y +10z) = 2 1 ​ (10x+20y+10z)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 10, x, plus, 20, y, plus, 10, z, right parenthesis, equals

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Answer:

The answer is "[tex]5x+10y+5z[/tex]"

Step-by-step explanation:

Given value:

[tex]\to \frac{1}{2}(10x + 20y +10z)[/tex]

Using the distributive property.

If there are three integers a,b and c then:

[tex]a \cdot(b+c) =a \cdot b + a \cdot c[/tex]

[tex]\to \frac{1}{2}(10x) +\frac{1}{2}(20y+10z)\\\\\to (5x) +\frac{1}{2}(20y+10z)[/tex]

Again apply the distributive property

 [tex]\to (5x) +(10y+5z)\\\\\to (5x+10y+5z)[/tex]

Or

[tex]\to \frac{1}{2}(10x + 20y +10z)[/tex]

take common 2 from the equation:

[tex]\to \frac{1}{2}\times 2 (5x + 10y +5z)\\\\\to (5x + 10y +5z)\\[/tex]

Answer:

5x+10y+5z

Step-by-step explanation:

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