Answer:
The direction of the vector is 115.33°
Explanation:
Polar Components of a Vector
One vector can be expressed in several forms. One of them is the polar form (r,θ) where r is the magnitude of the vector and θ is the angle formed by the vector and the positive x-axis direction.
If the rectangular components (x,y) of the vector are given, we can calculate the polar components as follows:
[tex]r=\sqrt{x^2+y^2}[/tex]
[tex]\displaystyle \tan\theta=\frac{y}{x}[/tex]
We are given the rectangular components of the vector B:
Bx= -1.33 m
By= 2.81 m
Note the vector lies on the second quadrant because the x-component is negative and the y-component is positive.
The direction of B is calculated below:
[tex]\displaystyle \tan\theta=\frac{2.81}{-1.33}[/tex]
[tex]\displaystyle \tan\theta= -2.1128[/tex]
[tex]\displaystyle \theta= \arctan -2.1128[/tex]
The scientific calculator gives:
[tex]\displaystyle \theta= -64.67^\circ[/tex]
We need to add 180° to give the correct angle in the second quadrant:
[tex]\theta= -64.67^\circ+180^\circ=115.33^\circ[/tex]
The direction of the vector is 115.33°